How would you prepare 385 ml of a 0.856 m NaOH solution starting with a 4.93 m stock solution
I assume you know the difference between 0.856 m and 0.856 M. Is this really m or should it be M?
should be M
That makes it easier.
Use mL1 x M1 = mL2 x M2
385*0856 = mL2 x 4.93
Solve for mL2.
Directions then would be, measure out mL2 volume of 4.93M solution and add enough water to make 385 mL. The final solution will be 0.856 M.
To prepare a 385 ml of a 0.856 M NaOH solution from a 4.93 M stock solution, you can use the dilution equation, which is given below:
M1V1 = M2V2
where:
M1 is the initial concentration of the solute (stock solution concentration)
V1 is the initial volume of the solute (stock solution volume)
M2 is the final concentration of the solute (desired concentration)
V2 is the final volume of the solute (desired volume)
In this case, the initial concentration (M1) is 4.93 M, and the desired concentration (M2) is 0.856 M. The desired volume (V2) is 385 ml.
Now, plug in these values in the dilution equation and solve for V1:
(4.93 M) x V1 = (0.856 M) x (385 ml)
V1 = (0.856 M * 385 ml) / 4.93 M
V1 = 66.894 ml
Therefore, you would need to measure 66.894 ml of the 4.93 M stock solution and then add enough solvent (typically deionized water) to bring the total volume up to 385 ml. This will result in a 0.856 M NaOH solution.