lim x→ ∞ of e^(−x) sin√x
A little lost. Help would be appreciated.
or lim sin√x/e^x . clearly x≥0
use an intuitive approach.
your numerator will be a number between -1 and 1, but your denominator keeps getting bigger and bigger
so a relatively constant around ±1 divided by a huge number ---> 0
so lim x→ ∞ of e^(−x) sin√x = 0
Wolfram agrees, look at the third case
http://www.wolframalpha.com/input/?i=limit+e%5E%28−x%29+sin√x