posted by Annie
I was doing a lab and stared off with 10mL of HNO3 and the mass of copper which was 1.5120g. The question now is:
With initial mass of copper wire being 1.5120g, calculate the volume of (16M) nitric acid that is required to fully react with the copper.
Cu(s)+2HNO3(aq) --> Cu(NO3)2(aq)+NO2(g)+H2O(l)
And to make any deviations between the original that was used in the experiment and what we calculated now.
calculate the moles of copper in 1.51grams. You need twice the moles of acid as moles of copper.
Volume acid in liters=molesacid/molarityacid