Ten ,one rupees coin are put on the top of at each other on a table each coin has a mass 'm' give the magnitudes and direction of - 1. The force of seventh coin (counted from bottom) due to all the coins. 2. The reaction of 6th coin on the 7th coin. 3. The force at 7th coin by 8th coin.
To determine the magnitudes and direction of the forces acting on the coins, we need to consider the concept of Newton's Third Law of Motion, which states that for every action, there is an equal and opposite reaction.
1. The force of the seventh coin due to all the coins:
To calculate this force, we need to consider all the coins that are above the seventh coin. Since each coin has a mass 'm', the force of gravity acting on each coin is equal to the weight, which is given by the equation: F = m * g, where 'g' is the acceleration due to gravity.
For the seventh coin, there are three forces acting on it from above:
- The force of the sixth coin, which we'll call F6
- The force of the fifth coin, which we'll call F5
- The force of the fourth coin, which we'll call F4
The net force on the seventh coin is the sum of all these forces: F7_net = F6 + F5 + F4.
2. The reaction of the sixth coin on the seventh coin:
According to Newton's Third Law, the reaction of the sixth coin on the seventh coin will be equal in magnitude but opposite in direction to the force exerted by the seventh coin on the sixth coin. Therefore, the reaction force of the sixth coin on the seventh coin is also F6.
3. The force of the eighth coin on the seventh coin:
Similarly, the force of the eighth coin on the seventh coin will be equal in magnitude but opposite in direction to the force exerted by the seventh coin on the eighth coin. Therefore, the force of the eighth coin on the seventh coin is F7.
Please note that the magnitude of forces F6, F5, F4, and F7 will depend on the mass of each coin and the acceleration due to gravity.
would it be n*mg where n is the coins above it?
Force on 7th coin is 3mg
force on 7th due to 8th is also 3mg