Please help me on this one!
ABCD
x 9
-----
DCBA
What is A,B,C,and D?
A = 1, otherwise the product would have 5 digits.
D = 9 because A = 1.
B = 0 or 1, otherwise the product would have 5 digits.
If B = 1, then C = 0, otherwise the product would have 5 digits.
But 1109 * 9 = 9981, which isn't right.
So B = 0. Then 9*D = 9*9 = 81, so 8 + 9*C ends with a 0 (B = 0). The only choice is C = 8
1089*9 = 9801
To find the values of A, B, C, and D in the multiplication problem:
ABCD
x 9
-----
DCBA
Let's solve it step by step.
Step 1: Start by multiplying D (the ones digit) by 9. This should give a result in the ones place.
D x 9 = C
So, C = D x 9
Step 2: Carry over any tens digit from the previous step (if applicable) and multiply C (the tens digit) by 9.
C x 9 = B
So, B = C x 9
Step 3: Carry over any tens digit from the previous step (if applicable) and multiply B (the hundreds digit) by 9.
B x 9 = A
So, A = B x 9
Step 4: Carry over any tens digit from the previous step (if applicable) and multiply A (the thousands digit) by 9.
A x 9 = 0 (since there is no next place value)
Therefore,
A = B x 9
B = C x 9
C = D x 9
In the given problem, A, B, C, and D are unknowns, so there is not enough information provided to determine their exact numerical values.
To solve this problem, we'll use a process called long multiplication. Let's start by multiplying the ones digit (D) of the top number (ABCD) by 9.
D multiplied by 9 gives us a product that ends with D, so D * 9 = D. We write the product under the line.
Next, we move to the tens digit (C) of the top number and multiply it by 9. In this case, C * 9 will give us a product that ends with A. So, C * 9 = A. We write A as the next digit under the line.
Next, we move to the hundreds digit (B) of the top number and multiply it by 9. In this case, B * 9 will give us a product that ends with B. So, B * 9 = B. We write B as the next digit under the line.
Lastly, we move to the thousands digit (A) of the top number and multiply it by 9. In this case, A * 9 will give us a product that ends with C. So, A * 9 = C. We write C as the final digit under the line.
Putting it all together, the final answer is ABCD = DCBA. From this equation, we can see that A = C, B = B, C = A, and D = D.
Therefore, A is equal to C, B is equal to B, C is equal to A, and D is equal to D.