How much work is done in lifting 450 lb of cement 75 ft above the ground?
So basically its W=fs
(450lb)(75ft)=33750lb
To find the work done in lifting the cement, we can use the formula W = fs, where W is the work done, f is the force applied, and s is the distance over which the force is applied.
In this case, the force applied is the weight of the cement, which is given as 450 lb. The distance over which the force is applied is 75 ft.
Therefore, the work done in lifting the cement can be calculated as:
W = (450 lb) * (75 ft)
Multiplying the two values, we get:
W = 33750 lb·ft
So, the work done is 33750 lb·ft.
To calculate the work done in lifting the cement, we must convert the units to a more appropriate system. Let's convert pounds (lb) to newtons (N) and feet (ft) to meters (m).
We know that 1 lb is approximately equal to 4.448 N, and 1 ft is approximately equal to 0.3048 m.
So, 450 lb is equal to (450 lb) × (4.448 N/lb) = 2001.6 N, and 75 ft is equal to (75 ft) × (0.3048 m/ft) = 22.86 m.
Now, we can calculate the work done using the formula W = fs.
W = (2001.6 N) × (22.86 m) = 45,687.5 N·m
Therefore, the work done in lifting 450 lb of cement 75 ft above the ground is approximately 45,687.5 N·m.