A canoe in still water travels at a rate of 12 miles per hour. The current today is traveling at a rate of 2 miles per hour. If it took an extra hour to travel upstream, how far was the trip one way?
about 33
about 35
about 37
about 39
That's a strange school subject.
That's what happens when you work on 1 question for and hour and 10 minutes.. You write strange school subjects.. plus complete and total frustration.
To find out the distance of the trip one way, we need to determine the rate of the canoe when it is traveling upstream.
Let's assume the distance of the trip one way is denoted by "x" miles.
When the canoe is traveling downstream (with the current), the effective rate is the sum of the canoe's speed and the current's speed. So, the downstream rate would be 12 mph + 2 mph = 14 mph.
When the canoe is traveling upstream (against the current), the effective rate is the difference between the canoe's speed and the current's speed. So, the upstream rate would be 12 mph - 2 mph = 10 mph.
We know that it took an extra hour to travel upstream, so we can set up the equation:
x / 10 = x / 14 + 1
To solve the equation, we can:
1. Multiply through by the common denominator of 14 to eliminate the fractions:
14x = 10x + 14
2. Subtract 10x from both sides of the equation to isolate the variable:
4x = 14
3. Divide both sides of the equation by 4 to solve for x:
x = 14 / 4 = 3.5
Therefore, the distance of the trip one way is approximately 3.5 miles.
None of the provided answer options (33, 35, 37, or 39 miles) match the calculated distance. Please double-check the options or provide the correct answer choices.