Block B has a mass of 4.2 kg and block A has a mass of 2.6 kg. They are in contact and slide over a frictionless horizontal surface. A force of 11 N acts on B.(force applied on block b then block a , they are beside each other)
what is the force on B due to A if the blocks are interchanged?
To find the force on Block B due to Block A when the blocks are interchanged, we need to consider the concept of Newton's third law of motion, which states that every action has an equal and opposite reaction.
When Block B is being subjected to a force of 11 N, it exerts an equal and opposite force on Block A. Therefore, the force exerted by Block A on Block B is also 11 N (as per Newton's third law).
When the blocks are interchanged, the masses of Block A and Block B remain the same. Therefore, the force exerted by Block B on Block A will still be 11 N and will be unaffected by the interchange.
So, the force on Block B due to A is still 11 N when the blocks are interchanged.
If the force is horizontal on B, pushing A
net force=totalmass*a
a=11/(4.2+2.6)
so the force pushing on A, and A pushing on B, is 2.6*a