Jose can paint a house in 10 days and peter can paint the same house in 12 days. How long will it take to paint the house if both men work?
It will take x days, where
1/x = 1/10 + 1/12
6 2/3
If Jose take leave for 1 day and Peter take leave for 2 days when they are working together to paint a house? How long will they finish to paint a house.
To find out how long it will take for both Jose and Peter to paint the house together, we can use the concept of work rates. The work rate represents the amount of work done per unit of time.
Let's first determine the work rates of Jose and Peter individually.
Since Jose can paint the house in 10 days, his work rate would be 1 house per 10 days.
Similarly, Peter's work rate would be 1 house per 12 days.
To determine their combined work rate, we need to add their individual work rates.
Jose's work rate + Peter's work rate = 1/10 + 1/12
To add fractions with different denominators, we need to find a common denominator. In this case, the least common multiple (LCM) of 10 and 12 is 60.
So, 1/10 + 1/12 = 6/60 + 5/60 = 11/60
This means that together, Jose and Peter can paint 11/60th of a house per day.
To find out how long it will take to paint the entire house, we can divide the total work (1 house) by their combined work rate (11/60).
1 / (11/60) = 60/11
Hence, it will take approximately 5.45 days for both Jose and Peter to paint the house if they work together.