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Mathematics
Algebra
Mixture Problems
A 70% acid solution is to be mixed with a 40% solution. How many gallons of each solutions are needed?
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depends what results you want.
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a chemist wants to mix a 22 acid solution with a 46% acid solution to get 32 gallons of 37% acid solution. How many gallons of
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just add up all the acid: .22x + .46(32-x) = .37*32
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How do you solve for this:how many gallons of a 10% alcohol solution be mixed with 20 gallons of a 10% acid solution to obtain
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Not 100% sure, but I think 5 gallons. 20 gallons of 10% acid meaning 2 gallons of acid + 18 gallon
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How many gallons of 5% acid solution should be mixed with 20 galllons of a 10% acid solution to obtain an 8% acid solution
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let the amount of the 5% solution that must be added be x gallons .05x + .10(20) = .08(20+x) times
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An 80% acid solution is to be mixed with a 30% solution to get 90 gallons of a 50% solution. How many gallons of each solution
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0.8x + 0.3(90-x) = .5(90) .8x + 27 -.3x = 45 .5x +27 = 45 .5x + 27 - 27 = 45-27 .5x = 18 x = 36 36
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How much pure acid should be mixed with 3 gallons of a 50% acid solution in order to get an
80% acid solution? The %'s always
Top answer:
i got 4.5. Did i do that right?
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60 ml of solution A is mixed with 120 ml of solution B to produce solution C which contains 8% of pure acid. If 80ml of solution
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To solve this problem, we need to set up a system of equations based on the given information. Let's
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A solid acid is dissolved in enough water to make 200 ml of a solution. 40.0ml of the solution is titrated to a phenolphthalein
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Looks like not enough information is there but it can be done. The easy way to understand it is to
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Solution A is 25% and solution B is 40% acid. How many gallons of each solution must be used in order to create a 50 gallon
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A+B=50 0.25A+0.40B=0.34(50) Solve for A and B.
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Suppose a 2% acid solution is mixed with a 3% acid solution. Find the percent of acid in each mixture.
-a mixture that contains
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equal amounts: 2.5% if 3% solution is x times the 2% solution, then if the resulting concentration
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Suppose a 2% acid solution is mixed with a 3% acid solution. Find the percent of acid in each mixture.
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.02*V+.03V=2V*percent percent= 2.5 .02*3V+.03V=4V*percent percent= (.06+.03)/4=9/4 percent or 2.25
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