A soccer ball is kicked from the ground with an initial speed of 19.4 m/s at an upward angle of 49.8˚. A player 48.5 m away in the direction of the kick starts running to meet the ball at that instant. What must be his average speed if he is to meet the ball just before it hits the ground? Neglect air resistance.

Ignore the 2nd half of the question at first (the player 48.5m away).

You need to find the range of the football. Work that out first.

After that compare that distance to where the player is. i.e. find the distance between where the ball lands and 48.5m.

Then remember that the ball is kicked and the player runs at the same time. So they both take the same time to get to the spot where the ball lands.

See if you can work it out now.

To solve this problem, we need to break it down into two parts: finding the time it takes for the ball to reach the player and then calculating the average speed the player needs to reach the ball in that time.

First, let's find the time it takes for the ball to reach the player. We can do this by using the vertical component of the initial velocity of the ball. The vertical velocity can be found by multiplying the initial speed of the ball (19.4 m/s) by the sine of the angle of elevation (49.8˚).

Vertical velocity (v_y) = initial speed (v) * sin(angle)

v_y = 19.4 m/s * sin(49.8˚)

Next, we can use the equation of motion to find the time it takes for the ball to reach the ground from its maximum height.

Vertical displacement (δy) = v_y * t - (1/2) * g * t^2

Since the ball reaches the ground, the vertical displacement is zero, and acceleration due to gravity (g) is -9.8 m/s^2.

0 = v_y * t - (1/2) * g * t^2

Solving this quadratic equation for t will give us the time it takes for the ball to reach the ground.

Once we have the time (t), we can calculate the average speed the player needs to reach the ball. The distance travelled by the player is equal to the distance between the player and the starting point of the ball (48.5 m).

Average speed = distance / time

Now let's put it all together and solve the problem step by step:

1. Calculate the vertical velocity of the ball:
v_y = 19.4 m/s * sin(49.8˚)

2. Calculate the time it takes for the ball to reach the ground:
0 = v_y * t - (1/2) * g * t^2

3. Solve the equation for t to find the time.

4. Calculate the average speed of the player:
Average speed = distance / time

By following these steps, you can determine the average speed the player needs to meet the ball just before it hits the ground.