Four times the sum of a number and 15 is at least 120. Let x represent the number. Find all possible values for x.
A. x ¡Ý 26
B. x ¡Ý ¨C15
C. x ¡Ý 15
D. x ¡Ý ¨C26
I tried it and cant find it.
4(x+15) >= 120
x+15 >= 30
x >= 15
Listen to Steve comment it’s correct
To find all possible values for x, we need to solve the equation given in the problem.
The equation states that "Four times the sum of a number and 15 is at least 120." Mathematically, this can be translated as:
4(x + 15) ≥ 120
To find the possible values for x, we can solve this inequality. Let's go step by step:
1. Distribute the 4 into the parentheses:
4x + 60 ≥ 120
2. Subtract 60 from both sides of the inequality:
4x ≥ 120 - 60
4x ≥ 60
3. Divide both sides by 4:
x ≥ 60/4
x ≥ 15
From this inequality, we can conclude that x is greater than or equal to 15 (x ≥ 15).
Therefore, the correct answer is:
C. x ≥ 15
A. x ¡Ý 26
B. x ¡Ý ¨C15
C. x ¡Ý 15
D. x ¡Ý ¨C26