You drop a rock off a bridge. The rock’s height, h (in feet above the water), after t seconds is modeled by h = -16t2 + 541. What is the height of the rock after 2 seconds?
A. –64 feet
B. 605 feet
C. 509 feet
D. 477 feet
I have no clue... please help
-16*2 squared (*2)= 32
64+541=605
your answer is B
thank you :) I got some more questions too plz help me blackveilbridesarmymember
To find the height of the rock after 2 seconds, you can use the given equation: h = -16t^2 + 541.
Simply replace t with 2 in the equation and calculate it:
h = -16(2)^2 + 541
h = -16(4) + 541
h = -64 + 541
h = 477
Therefore, the height of the rock after 2 seconds is 477 feet. Hence, the correct answer is option D.