I had asked a question.why when solid body with greater density than water is when dropped from floating boat water level rises? the answer has been given that as the solid body is more dense than water displaces less fluid as compared to when it was a part of floating boat.i understood all these but this explains HOW THE AMOUNT OF DISPLACED WATER DROPS OR DECREASES BUT I AM ASKING WHY LEVEL OF WATER FALL WHEN THIS SOLID BALL WAS DROPPED FROM BOAT?I MEAN ARE BOTH SAME THING. LEVEL OF WATER WILL FALL IF AMOUNT OF DISPLACED WATER DECREASES?I REALLY DON'T UNDERSTAND WHAT WE GENERALLY MEAN WHEN SAY THAT WATER IS DISPLACED. I MEAN I KNOW OBJECT DROPPED IN WATER TAKES SOME PLACE WHERE WATER WOULD HAVE BEEN PRESENT OTHERWISE THATS WHAT WE CALL DISPLACES WATER BUT WHERE THAT DISPLACED WATER GO?WHEN BOAT IS FLOATING IT DISPLACES WEIGHT OF FLUID EQUAL TO ITS OWN WEIGHT WHERE THAT DISPLACED WATER GO?I THINK THAT DISPLACED WATER RAISE THE LEVEL OF WATER RIGHT?

Question

I had asked a question.why when solid body with greater density than water is when dropped from floating boat water level rises? the answer has been given that as the solid body is more dense than water displaces less fluid as compared to when it was a part of floating boat.i understood all these but this explains HOW THE AMOUNT OF DISPLACED WATER DROPS OR DECREASES BUT I AM ASKING WHY LEVEL OF WATER FALL WHEN THIS SOLID BALL WAS DROPPED FROM BOAT?I MEAN ARE BOTH SAME THING. LEVEL OF WATER WILL FALL IF AMOUNT OF DISPLACED WATER DECREASES?I REALLY DON'T UNDERSTAND WHAT WE GENERALLY MEAN WHEN SAY THAT WATER IS DISPLACED. I MEAN I KNOW OBJECT DROPPED IN WATER TAKES SOME PLACE WHERE WATER WOULD HAVE BEEN PRESENT OTHERWISE THATS WHAT WE CALL DISPLACES WATER BUT WHERE THAT DISPLACED WATER GO?WHEN BOAT IS FLOATING IT DISPLACES WEIGHT OF FLUID EQUAL TO ITS OWN WEIGHT WHERE THAT DISPLACED WATER GO?I THINK THAT DISPLACED WATER RAISE THE LEVEL OF WATER RIGHT?

Answer 1

Ok, the total water displaced is equal to the weight of the boat and the object when it is in the boat.

When the object is thrown over, it displaces water equal to its VOLUME, not weight, and it sinks. The boat now displaces its weight.
So total water displaced is LESS when the object is thrown over and it sinks. The extra force holding up the boat and weight is now provided by the ground at the bottom pushing on the weight upwards.

Before: After
weightboat+weigh are supported by the sea bouyancy
After: the weight of the boat and weight is now supported by seabouyancy PLUS the sea bottom.
So, less water is displaced after the boat sinks.

Answer 2

I apologize for any confusion caused. I will explain further to address your question.

When we say that a solid object displaces water, it means that the object takes up space that was previously occupied by water. In other words, the object moves the water out of the way to make room for itself.

When a solid body with greater density than water is dropped from a floating boat, it displaces a volume of water equal to its own volume. This means that the water level in the container will initially rise when the object is placed in it. However, when the object is released from the boat, it sinks to the bottom and no longer occupies the space it previously filled. As a result, the water level decreases or falls because the volume of the object is no longer displacing water.

In the case of a floating boat, it displaces a volume of water equal to its weight. The water that is displaced by the boat will indeed raise the water level. This is due to Archimedes' principle, which states that an object immersed in a fluid experiences an upward buoyant force equal to the weight of the fluid displaced.

To summarize, when a solid object is dropped from a floating boat, the water level falls because the object no longer occupies the space it previously filled, and hence it does not displace water anymore. The water level rises when the object is initially placed in the water because it moves the water out of the way and takes up space.