Little Timmy falls down a well and hits the water 1.5s later. Determine the distance from the top of the well to the water below.
Just an equation would be fine.
Thanks in advance.
distance fell=1/2 g t^2
h = (1/2) g t^2
in metric, g = 9.81 meters/s^2
in English g = 32 feet/second^2
Thank you guys so much ! ^^
To determine the distance from the top of the well to the water, we can use the equation of motion for an object falling freely under gravity. The equation is:
h = (1/2) * g * t^2
Where:
h is the height or distance
g is the acceleration due to gravity (approximately 9.8 m/s^2 on Earth)
t is the time taken
In this case, we are given that Little Timmy falls for 1.5 seconds. Substituting the values into the equation:
h = (1/2) * 9.8 m/s^2 * (1.5 s)^2
Simplifying this equation, we get:
h = (1/2) * 9.8 m/s^2 * 2.25 s^2
h = 4.9 m/s^2 * 2.25 s^2
h ≈ 11.025 meters
Therefore, the distance from the top of the well to the water below is approximately 11.025 meters.