The combustion of hexane can be represented by the following equation:
__C6H14 (g) + __O2(g) → __CO2(g) + __H2O(g)
What is the mass of carbon dioxide produced?
How much hexane was burned? How much O2 was used?
To determine the mass of carbon dioxide produced, we need to use the balanced chemical equation and the molar masses of the compounds involved.
The balanced chemical equation for the combustion of hexane is:
2C6H14 (g) + 19O2(g) → 12CO2(g) + 14H2O(g)
From the balanced equation, we can see that for every 2 moles of hexane burned, 12 moles of carbon dioxide are produced.
To determine the mass of carbon dioxide produced, we need to know the molar mass of carbon dioxide. The molar mass of carbon dioxide (CO2) is:
Carbon (C) = 12.01 g/mol
Oxygen (O) = 16.00 g/mol (there are 2 oxygens in CO2)
So, the molar mass of carbon dioxide (CO2) is:
12.01 g/mol + 2 * 16.00 g/mol = 44.01 g/mol
Now, we can calculate the mass of carbon dioxide produced using the given equation:
Mass of CO2 = (moles of CO2) * (molar mass of CO2)
From the balanced equation, we know that 12 moles of CO2 are produced for every 2 moles of hexane burned.
Therefore, the mass of carbon dioxide produced is:
Mass of CO2 = (12 moles CO2 / 2 moles hexane) * (44.01 g/mol)
= 6 * 44.01 g = 264.06 g
Therefore, the mass of carbon dioxide produced during the combustion of hexane is 264.06 grams.
To determine the mass of carbon dioxide (CO2) produced during the combustion of hexane (C6H14), we need to balance the chemical equation and calculate the molar mass ratio.
The balanced equation for the combustion of hexane is:
2 C6H14 (g) + 19 O2(g) → 12 CO2(g) + 14 H2O(g)
From the equation, we can see that for every 2 moles of hexane (C6H14), we produce 12 moles of carbon dioxide (CO2).
Now, we need to know the molar mass of carbon dioxide, which is the sum of the atomic masses of carbon (C) and two oxygen (O) atoms:
Molar mass of CO2 = 12.01 g/mol (C) + 2 * 16.00 g/mol (O) = 44.01 g/mol
Next, we need to calculate the molar mass of hexane:
Molar mass of C6H14 = 6 * 12.01 g/mol (C) + 14 * 1.01 g/mol (H) = 86.18 g/mol
Finally, we can use the molar mass ratio to calculate the mass of carbon dioxide produced:
(12 moles CO2 / 2 moles C6H14) * (44.01 g/mol CO2 / 1 mole CO2) = 264.06 g of CO2
Therefore, the mass of carbon dioxide produced during the combustion of hexane is 264.06 grams.