A packaging freight 1.45 m by 21.0 cm by 29.0 cm has a mass of 155 kilograms find the stress (in k p a) exerted by the crate on the floor in each of the 3 possible positions my problem is I don't know how to convert this equation into kPa
To find the stress exerted by the crate on the floor, we need to know the contact area between the crate and the floor. Since there are three possible positions, let's consider each one separately.
Position 1: The crate is resting on its smallest side (21.0 cm by 29.0 cm).
To find the contact area, we multiply the length (29.0 cm) by the width (21.0 cm):
Area = 21.0 cm * 29.0 cm = 609.0 cm²
Next, we need to convert the mass from kilograms to newtons since stress is measured in force per unit area (N/m² or Pascal). We know that 1 kilogram corresponds to 9.8 newtons (N) due to gravity.
Force = Mass * Gravity
Force = 155 kg * 9.8 N/kg = 1519 N
Now, let's calculate the stress in kPa (kiloPascals), which is a commonly used unit for expressing stress.
1 kPa = 1000 N/m²
Stress = Force / Area
Stress = 1519 N / 609.0 cm² = 2.496 N/cm²
To convert from N/cm² to kPa, divide by 1000 since 1 kPa = 1000 N/m²:
Stress = 2.496 N/cm² / 1000 = 0.002496 kPa
So, in position 1, the stress exerted by the crate on the floor is approximately 0.002496 kPa.
You can follow a similar process to calculate the stresses in the other two possible positions. Remember to calculate the contact area and convert the stress to kPa by dividing by 1000.