What is the rate of deceleration of a 1400-kg SUV that is going 75.0 km/h and then slows to 25.0 km/h in 8.20 s?
Figured it out,
Don't worry about the mass, just solve for Deceleration. which is deltavelocity/delta time
>>Subtract First(75 - 25) = 50 km/hr*(1hr/3600 sec) = 50/3600 = 0.01389 km/s. <<Dont Forget the conversion to sec
>>>Then delta velocity/ delta time = 0.01389/8.2 = 0.001694 km/s^2 = 1.7 m/s^2
To find the rate of deceleration, we can use the equation:
acceleration = (final velocity - initial velocity) / time
First, we need to convert the initial and final velocities from km/h to m/s.
Given:
Initial velocity (v₁) = 75.0 km/h
Final velocity (v₂) = 25.0 km/h
Time (t) = 8.20 s
Converting km/h to m/s:
1 km/h = 0.2778 m/s
Initial velocity in m/s (v₁) = 75.0 km/h * 0.2778 m/s = 20.83 m/s
Final velocity in m/s (v₂) = 25.0 km/h * 0.2778 m/s = 6.94 m/s
Now, let's substitute the values into the equation:
acceleration = (v₂ - v₁) / t
= (6.94 m/s - 20.83 m/s) / 8.20 s
Calculating:
acceleration = (-13.89 m/s) / (8.20 s)
= -1.69 m/s²
Therefore, the rate of deceleration of the SUV is approximately -1.69 m/s² (negative sign indicates deceleration).