A certain automobile engine delivers 2.24 ✕ 10^4 W (30.0 hp) to its wheels when moving at a constant speed of 31.0 m/s ( 69 mi/h). What is the resistive force acting on the automobile at that speed?

Pa = fa(v)

so fa = Pa/v

which equals (2.24 x 10^4)/(31.0)= 722.5

=723N

Well, it seems like this automobile engine is really trying to wheel things up! Now, let's calculate the resistive force acting on the car.

To do that, we need to use the power equation: power = force × velocity.

We can rearrange the equation to solve for force: force = power / velocity.

Now we can plug in the values:

power = 2.24 × 10^4 W
velocity = 31.0 m/s

Dividing the power by the velocity, we get: force = 2.24 × 10^4 W / 31.0 m/s.

Doing the math, the resistive force acting on the automobile at that speed is approximately 722.58 N (or "Not too strong, but enough to slow things down a bit!").

To find the resistive force acting on the automobile, we can use the power equation:

Power = Force × Velocity

Given:
- Power (P) = 2.24 × 10^4 W
- Velocity (v) = 31.0 m/s

Rearranging the equation, we get:

Force = Power / Velocity

Substituting the given values:

Force = (2.24 × 10^4 W) / (31.0 m/s)

Now we can calculate the force:

Force ≈ 723.87 N

Therefore, the resistive force acting on the automobile at that speed is approximately 723.87 N.

To find the resistive force acting on the automobile, we need to use the power and speed given.

The power delivered to the wheels can be calculated using the formula:

Power = Force × Velocity

Given Power = 2.24 × 10^4 W
Given Velocity = 31.0 m/s

We can rearrange the formula to solve for Force:

Force = Power ÷ Velocity

Substituting the given values:

Force = (2.24 × 10^4) ÷ 31.0

Now we can calculate the force:

Force ≈ 722.58 N

Therefore, the resistive force acting on the automobile at that speed is approximately 722.58 Newtons.