the sum of two whole numbers is an even number. one of the numbers is even. can a deduction be made about the other number?
Yes.
HOW??
Can you please give me some example? I will appreciate.
2 + 3 = ?
7 * 10 = ?
15 + 20 = ?
3 + 3 = ?
10 + 10 = ?
18 + 8 = ?
If the numbers are m and n, and m is even, then m=2k. If the sum is even, say 2x, then
2k+n = 2x
n = 2x-2k = 2(x-k)
So, it is clear that n is also even, since it is a multiple of 2.
Yes, a deduction can be made about the other number in this scenario.
To understand why, let's break down the problem step by step. We know that the sum of two whole numbers is an even number, and we also know that one of the numbers is even.
First, let's consider the definition of an even number. An even number is any integer that is divisible by 2. For example, 2, 4, 6, and so on.
Since the sum of two whole numbers is an even number, there are two possibilities:
1. Case 1: The other number is even.
If one of the numbers is even and the sum is even, it means that the other number must be even as well. For example, if one number is 4, then the sum with any other even number (e.g., 2, 6, 8, etc.) will always be an even number.
2. Case 2: The other number is odd.
If one of the numbers is even and the sum is even, it means that the other number cannot be odd because the sum of an even number and an odd number is always odd. For example, if one number is 4, then the sum with any odd number (e.g., 1, 3, 5, etc.) will always be an odd number.
In conclusion, if the sum of two whole numbers is an even number and one of the numbers is even, then we can deduce that the other number must also be even.