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Factor Completely
8y^5+12y^3+4y
1 answer
4y(2y^4+3y^2+1)
4y(2y^2+1)(y^2+1)
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factor completely 3y^3 - 12y
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Factor Completely
8y^5+12y^3+4y
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looks like a common factor of 4y can you finish it?
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Rewrite the following expression using Distributive Property 12(y - 0) (1 point) Responses 12y - 120 12y - 120 0 0
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lol, i also have these
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Rewrite the following expression using Distributive Property 12(y - 0) (1 point) Responses 12y - 120 12y - 120 0 0 12y-12 12y-12
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