I already know the angle of Eastdale which is 45° due to the turn from due east to the northwest. So therefore so I need to find the measures of angle c and angle n. I can use the Law of Sines.
sin‹C/c=sin‹E/e
sin‹C/18=(√2/2)/12.7308
sin‹C=18(√2/2)/12.708=.9998
angle c= 88.8°
So therefore m‹N= 180°-45°-88.8°=46.2°
What did I do wrong?
It seems like there was a decimal calculation error in your calculations. Let's double-check the calculations:
Using the Law of Sines:
sin(C)/18 = (sqrt(2)/2)/12.7308
sin(C) = 18 * (sqrt(2)/2)/12.7308
sin(C) = 0.9998
C ≈ arcsin(0.9998) ≈ 89.9° (rounded to one decimal place)
To find the measure of angle n:
m∠N = 180° - m∠E - m∠C
m∠N = 180° - 45° - 89.9° ≈ 45.1° (rounded to one decimal place)
So, the correct measures of angle C and angle N are approximately 89.9° and 45.1°, respectively.