You need to prepare 400 ml of a 4M glucose solution. It's chemical formula is C6H12O6 and its formula weight (FW) 180.16. Must show all work and calculation and then list what you will mix together to prepare the correct amount of this solution.


180.16 of glucose/400ml = x/4M

400*x 180.16*4

400x = 720.64

400/400

720.64/400 = 1.80

x= 1.80

I don't know where to go from here.

I'm not sure you can get there with that route.

mols glucose needed = 4 M x 0.400 L = ?
Then mols = grams/molar mass. You know mols and molar mass, solve for grams.

To prepare a 4M glucose solution with a total volume of 400 ml, we can follow these steps:

Step 1: Calculate the amount of glucose (in grams) needed:
To determine the grams of glucose required, we apply the formula weight (FW) of glucose, which is 180.16 g/mol, and the desired molarity (4M), and the volume (400 ml) using the formula:

moles of solute = Molarity x Volume (in liters)

moles of glucose = 4 M x 0.4 L = 1.6 moles

mass of glucose (in grams) = moles x FW
mass of glucose = 1.6 moles x 180.16 g/mol
mass of glucose = 288.26 grams

Step 2: Determine the amount of solvent (water) needed:
Since we want to prepare a solution with a final volume of 400 ml, we subtract the calculated mass of glucose from the desired total volume:

volume of solvent (water) = total volume - volume of glucose
volume of solvent = 400 ml - 400 ml = 0 ml

Step 3: Mix the components:
In this case, since the volume of the solvent is 0 ml, we will only need to mix 288.26 grams of glucose with no added solvent.

Therefore, to prepare the correct amount of the 4M glucose solution, you will need to mix 288.26 grams of glucose with no added solvent.