Two cylindrical copper wires have the same mass and are at the same temperature. Wire A is twice as long as wire B. The resistance of wire A is related to that of wire B by

a) RA = RB/4
b) RA = RB/2
c) RA = RB
d) RA = 2RB
e) RA = 4RB

jebem ti mrtve

To determine the relationship between the resistances of the two copper wires, we need to consider the factors that affect resistance.

Resistance (R) is related to the length (L) and cross-sectional area (A) of the wire, as well as its resistivity (ρ). The general formula for resistance is:

R = ρ * (L / A)

Given that both wires have the same mass and temperature, we can assume that they are made of the same material and have the same resistivity. Therefore, the relationship between their lengths and resistances can be determined.

Let's compare the lengths of the two wires:

Wire A is twice as long as wire B, which can be denoted as L(A) = 2 * L(B).

Now, let's substitute these lengths into the formula for resistance:

R(A) = ρ * (L(A) / A)
R(A) = ρ * (2 * L(B) / A)
R(A) = (2 * ρ * L(B)) / A

Now, we have the formula for R(A) in terms of L(B) and A. We can notice that the value (2 * ρ * L(B)) is equal to the formula for R(B):

R(B) = ρ * (L(B) / A)

Therefore, we can conclude that R(A) is equal to R(B):

R(A) = R(B)

The correct answer is c) RA = RB.