Algebra

posted by Raven

The units digit of a two-digit number is two more than four times the tens digit. When the digits are reversed, the new number is thirteen more than three times the original number. What is the original number?

Please use algebraic equations to justify your answer.

  1. Damon

    (10 x + y)

    y = 2 + 4 x

    13 + 3 (10 x + y) = (10 y + x)

    13 + 30 x + 3 y = 10 y + x

    29 x + 13 = 7 y = 7 (4x+2)

    29 x + 13 = 28 x + 14

    x = 1
    then y = 4x+2 = 6
    so
    16

  2. Raven

    Thank you so much.

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