Calculate the volume in liters of a M copper(II) sulfate solution that contains of copper(II) sulfate . Round your answer to significant digits.
Please re-read your post and note you can't work the problem without numbers.
To calculate the volume of a copper(II) sulfate solution, we need two pieces of information: the mass of the copper(II) sulfate and its concentration in the solution.
Let's break down the steps:
Step 1: Determine the number of moles of copper(II) sulfate.
To find the number of moles, divide the mass of copper(II) sulfate by its molar mass.
You will need to know the molar mass of copper(II) sulfate. The formula for copper(II) sulfate is CuSO4, and the molar masses are:
Copper (Cu): 63.55 g/mol
Sulfur (S): 32.06 g/mol
Oxygen (O): 16.00 g/mol (there are four oxygen atoms in the formula)
So, the molar mass of CuSO4 is:
(1 * 63.55 g/mol) + (1 * 32.06 g/mol) + (4 * 16.00 g/mol) = 159.61 g/mol
Step 2: Convert the mass of copper(II) sulfate to moles.
Divide the mass of copper(II) sulfate by its molar mass to get the number of moles.
Step 3: Calculate the volume of the solution.
Use the concentration of the solution to calculate the volume. Concentration is typically given in moles per liter (mol/L).
Since the concentration is not provided in the question, we cannot determine the volume in liters without that information.
Once you have the concentration, divide the number of moles by the concentration to get the volume in liters.
Remember to round your final answer to the appropriate number of significant digits as indicated in the question.