During one year in a school, 5/8 of the students had measles, 1/2 had chicken pox and 1/8 had niether. What fraction of the school had both measles and chicken pox
5/8-x+x+1/2-x+1/8=1
-x and +x cancel
5/8+1/2+1/8-x lcm
5+4+1 - x=
/8
10/8-x=1
10/8-1=x
Lcm
10-8
/8=x
2/8=x.
a man made a will in which he left 4/9 of his money to his wife and 2/5 of the remainder to his eldest child, the rest was to be shared equally among his four younger children. if each of the younger children received 54,000 Naira, what was the wife's share?
Answer
Well, it sounds like this school was quite the party for germs! To find out what fraction of the school had both measles and chicken pox, we need to start by finding the fractions of students who had each of the diseases separately.
So, if 5/8 of the students had measles, that means 3/8 did not.
If 1/2 had chicken pox, that means the other half also did not.
Now, don't forget the 1/8 of students who had neither. They're kind of like the unicorns in this scenario.
To find the fraction of students who had both diseases, we need to subtract the fractions who didn't have each disease.
If 3/8 did not have measles, that means 1 - 3/8 = 5/8 did have measles.
And if 1/2 did not have chicken pox, that means 1 - 1/2 = 1/2 did have chicken pox.
So, the fraction of students who had both measles and chicken pox is 5/8 * 1/2 = 5/16.
Therefore, 5/16 of the school had both measles and chicken pox. Quite the tag team duo!
To find the fraction of the school that had both measles and chickenpox, we need to subtract the fractions of students who had only measles, only chickenpox, and neither from the total.
Let's assume that there are 8 students in the school. We'll use this number to make the calculations easier.
Given information:
- 5/8 of students had measles.
- 1/2 of students had chickenpox.
- 1/8 of students had neither measles nor chickenpox.
To find the fraction of students who had both measles and chickenpox, we subtract the fractions of students who had only measles, only chickenpox, and neither from the total:
Total fraction of students = 8/8 = 1
Fraction of students with only measles = 5/8
Fraction of students with only chickenpox = 1/2
Fraction of students with neither measles nor chickenpox = 1/8
Adding these fractions:
5/8 + 1/2 + 1/8 = 5/8 + 4/8 + 1/8 = 10/8 = 1 and 2/8
Now, we subtract this total from 1 to find the fraction of students who had both measles and chickenpox:
1 - 1 and 2/8 = 8/8 - 2/8 = 6/8
Therefore, the fraction of the school that had both measles and chickenpox is 6/8.
5/8 + 1/2 = 9/8
Only 7/8 were sick, so 2/8 had both