A baseball is thrown vertically upward with a speed of 17.8 m/s from a height of 1.11 m. How high does the ball rise from its original position?
To find out how high the baseball rises from its original position, we can use the equations of motion for vertical motion.
First, let's identify the known values:
Initial velocity (u) = 17.8 m/s (upward)
Initial height (h) = 1.11 m
Final height (unknown) = ?
Acceleration due to gravity (g) = 9.8 m/s^2 (downward)
We can use the equation:
h = u^2 / (2g)
Plugging in the values:
h = (17.8 m/s)^2 / (2 × 9.8 m/s^2)
h = 316.84 m^2/s^2 / 19.6 m/s^2
h = 16.1796 m
Therefore, the ball rises approximately 16.18 meters from its original position.