Linda did 24 problems out of 25 correctly.In the next test she did twice as many examples correctly but received a mark only half as good.How many problems were there in the second test?
questions in 2nd test --- x
so 48/x = (1/2)(24/25)
48/x = 24/50
24x = 2400
x = 100
There were 100 problems
check:
1st test = 24/25 = 96%
2nd test = 48/100 = 48% , which is 1/2 of 96%
Well, it seems like Linda really improved in the second test, but didn't get the recognition she deserved. Nevertheless, let's do some math, clown style!
If Linda did 24 out of 25 problems correctly in the first test, she only got one problem wrong. In the second test, she did twice as many examples correctly, which means she did 48 problems right.
Now, let's talk about the mark. If she got half as good a mark, that means she received half the points for each problem. So, she received half a mark for each of the 48 problems she got right.
Assuming every problem is supposed to be worth one mark, we can conclude that she received a total of 24 marks in the second test. So, there were 24 problems in the second test.
Keep on cracking those clown questions!
Let's break down the information step-by-step:
1. Linda did 24 problems out of 25 correctly in the first test.
2. In the second test, she did twice as many examples correctly.
3. However, she received a mark only half as good.
Given this information, we can calculate the number of problems in the second test.
Step 1: Calculate the number of problems Linda solved correctly in the second test.
In the first test, Linda solved 24 problems correctly out of 25.
Therefore, in the second test, she would have solved 2 * 24 = 48 problems correctly.
Step 2: Calculate the mark Linda received in the second test.
Linda received a mark only half as good compared to the first test.
In the first test, Linda received a mark of 25.
Therefore, the mark she received in the second test would be 25 / 2 = 12.5.
Step 3: Determine the number of problems in the second test.
Since Linda received a mark of 12.5 for the second test, we can determine the ratio of problems to marks.
25 problems correspond to a 25-mark system in the first test.
Therefore, 12.5 marks would correspond to 25 * (12.5 / 25) = 12.5 problems in the second test.
Thus, there were 12.5 problems in the second test.
To find the number of problems on the second test, we need to use the information provided.
We know that Linda did 24 problems out of 25 correctly on the first test. This gives us a success rate of 24/25.
In the second test, Linda did twice as many examples correctly. Let's call the number of problems on the second test "x". So, she did 2x problems correctly.
We are also told that Linda received a mark only half as good on the second test. This means her success rate on the second test was (1/2)*(24/25).
We can now set up an equation to solve for x:
(2x) / x = (1/2)*(24/25)
To simplify the equation, we can cancel out the common factors:
2/1 = 12/25
Cross multiplying, we get:
2 * 25 = 12 * 1
50 = 12
This is not possible, so there is an error in the information given. Please double-check the details and provide the correct information.
24/25 correct is a 96% score
If she only did half as good then she got
96/2=48% on the second test
She also got twice as many problems correct.
24*2=48
In this problem the number of problem she got correct is also her percentage.
48 divided by what number will give her a score of 48%