A heat pump releases 103.0 kcal as it removes 54.0 kcal at the evaporator coils. how much work does this heat pump ideally accomplish? Answer should be in KJ
To find the work done by the heat pump, we need to use the equation:
Work = Heat released - Heat absorbed
Given that the heat released is 103.0 kcal and the heat absorbed is 54.0 kcal, we can substitute these values into the equation and convert the units to kilojoules:
Work = (103.0 kcal - 54.0 kcal) * (4.184 kJ/kcal)
= 49.0 kcal * (4.184 kJ/kcal)
= 204.116 kJ
Therefore, the heat pump ideally accomplishes 204.116 kJ of work.