Math

posted by Gwen

Decide whether each equation has one solution, no solution, or infinitely many solutions.
2(x-3)=2x
A. One Solution
B. No solutions
C. Infinitely many solutions
Is the answer A?

  1. Mia

    Can you show me how you came up with that answer? I like to see a person's though process. It helps me to assist you better.

  2. Gwen

    Well I did 2*x and 2*3=6
    2x-6=2x
    2*4-6=2
    2*4=8
    So wouldn't that be one solution.
    If that's not how to solve can you help me figure out how to do it?

  3. Mia

    Okay you first step is first when you multiply it you will get

    2x-6=2x

    After this you are trying to get x by itself. What would you do?

  4. Gwen

    Um I don't know how to do that if you could please help me to figure it out.

  5. Gwen

    2x-6=2x
    2-2=0
    6-2=4
    x=4
    Would that be one solution.

  6. Mia

    2x-6=2x

    Subtract 2x from both sides in order to get your x variables on 1 side

    2x-6=2x
    -2x -2x

    What you do to one side you must also do to the other. This leaves you with

    -6=0x

    Because it says 0x there is no solution

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