An electron has an initial speed of
2.24 × 10^5 m/s.
If it undergoes an acceleration of
2.2 × 10^14 m/s^2, how long will it take to reach a speed of 5.37 × 10^5 m/s
V = Vo + a*t
t = (V-Vo)/a =
t = (5.37*10^5-2.24*10^5)/2.2*10^14 =
3.13*10^5/2.2*10^14 = 1.42*10^-9 s.
To find the time it takes for the electron to reach a speed of 5.37 × 10^5 m/s, we can use the equation:
v = u + at
where:
- v is the final velocity (5.37 × 10^5 m/s)
- u is the initial velocity (2.24 × 10^5 m/s)
- a is the acceleration (2.2 × 10^14 m/s^2)
- t is the time we want to find
Rearranging the equation, we have:
t = (v - u) / a
Let's substitute the given values into the equation to find the time:
t = (5.37 × 10^5 m/s - 2.24 × 10^5 m/s) / (2.2 × 10^14 m/s^2)
We now have all the values we need to calculate the time it takes for the electron to reach the given speed. Let's do the math:
t = (3.13 × 10^5 m/s) / (2.2 × 10^14 m/s^2)
To simplify the calculation, we can divide both the numerator and denominator by 10^5:
t = (3.13) / (2.2 × 10^9 s)
Now, divide 3.13 by 2.2 to find the final value of t:
t ≈ 1.42 × 10^(-9) s
Therefore, it will take approximately 1.42 × 10^(-9) seconds for the electron to reach a speed of 5.37 × 10^5 m/s.