A helicopter weighs 3920 newtons, caculated the force on it if it is ascending up at a rate of 2m/s squre ,what wil b force on helicopter if it is moving up with the constant speed of 4m/s .

weight of helicopter is given so mass can be calculated as m = F/a = 3920/9.8 = 400kg.

Upward Force on helicopter is causing it to go upward so: F = W + m*a
F = 3920 + 400*2
F = 3920 + 800
F = 4720 this is the required Force...

weight of helicopter is given so mass can be calculated as m = F/a = 3920/9.8 = 400kg.

Upward Force on helicopter is causing it to go upward so: F = W + m*a
F = 3920 + 400*2
F = 3920 + 800
F = 4720 this is the required Force...

F=ma

m= F/a
m= 3920/9.8
m= 400 kg

F= W+ma
F= 3920+400×2
F= 3920+800
F= 4720
This is the value of F1

Now calculating F2

F= 4720-800
F= 3920

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To calculate the force on the helicopter in both scenarios, we need to use Newton's second law of motion which states that force (F) is equal to mass (m) multiplied by acceleration (a).

1. When the helicopter is ascending up at a rate of 2 m/s^2:
Given:
Mass of the helicopter (m) = 3920 Newtons (weight)
Acceleration (a) = 2 m/s^2

Equation: F = m * a
F = 3920 N * 2 m/s^2
F = 7840 N

Therefore, the force on the helicopter when it is ascending up at a rate of 2 m/s^2 is 7840 Newtons.

2. When the helicopter is moving up with a constant speed of 4 m/s:
In this scenario, the acceleration of the helicopter is zero since it is moving at a constant speed. Therefore, according to Newton's second law, the force on the helicopter will be zero.

Thus, the force on the helicopter when it is moving up with a constant speed of 4 m/s is zero.

Please note that this calculation assumes the absence of any other external forces acting on the helicopter aside from gravity.