How much heat will be released when 0.750 moles of carbon monoxide (CO) react in an excess of oxygen gas?
2CO(g) + O2(g) �¨ 2CO2(g) + 566 kJ
566 kJ/2 mol x 0.750 mols = ?
DrBob222
Please help me here!
How do we do charge balance and mass balance?
Plz give me an answer on a general basis so that i can do it for any compound i get. Thanks
All you ever wanted to know about charge balance:
http://ramsey1.chem.uic.edu/audrey/chem222/assign_docs/fall_12/mass_charge_ANS.pdf
All you ever wanted to know about mass balance.
http://mimoza.marmara.edu.tr/~zehra.can/CHEM209/6.%20Mass%20Balance%20Charge%20Balance.pdf
both:
https://answers.yahoo.com/question/index?qid=20130220200121AApLMNn
To calculate the amount of heat released when 0.750 moles of carbon monoxide (CO) react in an excess of oxygen gas, we need to use the balanced equation and the stoichiometry of the reaction.
The balanced equation is:
2CO(g) + O2(g) -> 2CO2(g) + 566 kJ
From the balanced equation, we can see that 2 moles of CO produce 2 moles of CO2 and release 566 kJ of heat. This means that for every 2 moles of CO, 566 kJ of heat is released.
To find the amount of heat released when 0.750 moles of CO reacts, we can set up a proportion using the mole ratio:
2 moles CO / 2 moles CO2 = 0.750 moles CO / x
Cross-multiplying the equation gives us:
2 moles CO * x = 2 moles CO2 * 0.750 moles CO
x = (2 moles CO2 * 0.750 moles CO) / 2 moles CO
x = 0.750 moles CO2
So, 0.750 moles of carbon monoxide (CO) reacting in an excess of oxygen gas will produce 0.750 moles of carbon dioxide (CO2) and release 566 kJ of heat.