While entering a freeway, a car accelerates from rest at a rate of 2.3 m/s2 for 12 s.How far does the car travel in those 12 s, in meters?
To calculate the distance traveled by the car in those 12 seconds, we can use the formula:
distance = initial velocity * time + (1/2) * acceleration * time^2
Given that the car starts from rest (initial velocity = 0 m/s) and accelerates at a rate of 2.3 m/s^2 for 12 seconds, the formula becomes:
distance = 0 * 12 + (1/2) * 2.3 * 12^2
Simplifying the equation:
distance = (1/2) * 2.3 * 144
Calculating further:
distance = 1.15 * 144
Finally, calculating:
distance = 165.6 meters
Therefore, the car travels a distance of 165.6 meters in those 12 seconds.
To find the distance the car travels in 12 seconds, we can use the equation for distance with constant acceleration:
d = v0 * t + (1/2) * a * t^2
Where:
d is the distance traveled,
v0 is the initial velocity (which is 0 as the car starts from rest),
t is the time (12 seconds in this case),
and a is the acceleration (2.3 m/s^2 in this case).
Plugging in the values into the equation, we have:
d = 0 * 12 + (1/2) * 2.3 * (12)^2
First, let's simplify the equation:
d = 0 + (1/2) * 2.3 * 144
d = (1/2) * 2.3 * 144
Next, perform the multiplication:
d = 1.15 * 144
d = 165.6
Therefore, the car travels a distance of 165.6 meters in those 12 seconds.