I'm kind of stuck on how to do this. Can someone help me? Thanks!
Write the equation of the line with slope -2 that passes through the point (-1, -3) in slope-intercept form.
start with point-slope form:
y+3 = -2(x+1)
Now just rearrange terms to the form you want.
y+3 = -2(x+1)
so
y = -2x-5
Sure! I can help you with that. To write the equation of a line in slope-intercept form (y = mx + b), you need two pieces of information: the slope (m) and a point the line passes through.
In this case, the slope is given as -2, and the line passes through the point (-1, -3).
To find the equation, we'll substitute the given values into the slope-intercept form equation and solve for the y-intercept (b).
Step 1: Start with the slope-intercept form equation: y = mx + b.
Step 2: Substitute the given slope value: y = -2x + b.
Step 3: Substitute the coordinates of the given point (-1, -3): -3 = -2(-1) + b.
Step 4: Simplify the equation: -3 = 2 + b.
Step 5: Solve for the y-intercept (b): -3 - 2 = b, so b = -5.
Step 6: Substitute the value of b back into the equation: y = -2x - 5.
Therefore, the equation of the line with slope -2 that passes through the point (-1, -3) in slope-intercept form is y = -2x - 5.
I hope that helps you! Let me know if there's anything else I can assist you with.