Modern oil tankers weigh over a half-million tons and have lengths of up to one-fourth mile. Such massive ships require a distance of 4.8 km (about 3.0 mi) and a time of 22 min to come to a stop from a top speed of 26 km/h.

(a) What is the magnitude of such a ship's average acceleration in m/s2 in coming to a stop?

49 To find the magnitude of the ship's average acceleration, we can use the equation:

acceleration = (final velocity - initial velocity) / time

First, let's convert the units:

Top speed = 26 km/h
Time = 22 min

We need to convert these values to meters per second to be consistent with the SI unit system.

1 km/h is equal to 1000 meters / 3600 seconds.
So, the top speed is 26 km/h × (1000 m / 3600 s) = 26 × (5/18) m/s = 130/18 m/s.

Now, let's convert the time. 1 minute is equal to 60 seconds.
Therefore, the time is 22 min × 60 s/min = 1320 seconds.

Now we have all the values needed to calculate the average acceleration:

acceleration = (0 m/s - 130/18 m/s) / 1320 s

Simplifying the equation:

acceleration = -130/18 m/s / 1320 s

Dividing the numerator by the denominator:

acceleration = -130/18 / 1320 m/s²

Finally, calculating the magnitude of the average acceleration:

magnitude of acceleration = | -130/18 / 1320 | m/s²

Which gives us the final answer.