A flower pot is thrown out of a window with a horizontal velocity of 8 m/s. If the window is 1.5 m off the ground, how far from the window does it land?
2.4
To find how far from the window the flower pot lands, we need to consider two things: the horizontal velocity and the time it takes for the flower pot to reach the ground.
First, let's find the time it takes for the flower pot to reach the ground. We can use the equation of motion for free-falling objects:
h = (1/2)gt^2
where h is the height, g is the acceleration due to gravity (approximately 9.8 m/s^2), and t is the time.
In this case, the height h is given as 1.5 m. Rearranging the equation, we have:
t = sqrt(2h/g)
t = sqrt(2 * 1.5 / 9.8)
t = sqrt(0.306)
t ≈ 0.55 seconds
Next, let's find the horizontal distance the flower pot travels in this time. We can use the formula:
d = vt
where d is the distance, v is the horizontal velocity, and t is the time.
In this case, the horizontal velocity v is given as 8 m/s, and t is approximately 0.55 seconds.
d = 8 * 0.55
d ≈ 4.4 meters
Therefore, the flower pot lands approximately 4.4 meters away from the window.