Let E and F be two events for which the probability of atleast one of them occurs is 3/4. what is the probability that neither E nor F will occur.
To find the probability that neither event E nor F will occur, we need to subtract the probability of at least one of them occurring from 1.
Let's denote the probability of event E occurring as P(E) and the probability of event F occurring as P(F).
We are given that the probability of at least one of the events occurring is 3/4. Mathematically, this can be written as:
P(E or F) = 3/4
Now, the probability that neither E nor F will occur can be written as:
P(neither E nor F) = 1 - P(E or F)
So, we need to find the value of P(E or F) first.
To do that, we can use the concept of the probability of the union of two events:
P(E or F) = P(E) + P(F) - P(E and F)
However, we do not have the values of P(E) and P(F), nor do we have the value of P(E and F). Therefore, we need some additional information to solve this problem.
Is there any other information or probabilities provided regarding events E and F?