physics
posted by Gaby .
When the Sun is directly overhead, a hawk dives toward the ground with a constant velocity of 4.80 m/s at 50.5° below the horizontal. Calculate the speed of her shadow on the level ground.
What i have done:
x= rcos(theta)
x=4.80m/s*cos(309.5)
x=3.05m
y=rsin(theta)
y=4.80m/s*sin(309.5)
y=3.70m
i know to calculate speed the equation is v=d/t but there is no time stated in the problem... I came to the conclusion that the constant velocity is the speed, is that right?
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