algebra

posted by barbara

An investment adviser invested $14,000 in two accounts. One investment earned 4% annual simple interest, and the other investment earned 2.5% annual simple interest. The amount of interest earned for 1 year was $458. How much was invested in each account?

  1. Henry

    Invested $X @ 4%.
    Invested $(14,000-X) @ 2.5%.

    0.04X + 0.025(14000-X) = $458.
    Solve for X.

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