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(y^3)^-2 (y^2)^0÷y^-3

the answer is1/y^3. I just don't understand how is that answer.

Please explain

(y^3)^-2(y^2)^0/y^-3 =

y^-6*y^0/y^-3 = y^-6/y^-3 = y^-3 = 1/y^3

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