Find the attractive force bet a 50 kg girl and a 60 kg boy, if they stand 2.00 m apart.
force=G m1 m2/distance^2
To find the attractive force between the girl and the boy, we can use the formula for gravitational force:
F = (G * m1 * m2) / r^2
Where:
F is the attractive force between the two objects
G is the gravitational constant, approximately equal to 6.674 × 10^-11 N(m/kg)^2
m1 and m2 are the masses of the two objects
r is the distance between the centers of the two objects
Here, the girl has a mass of 50 kg and the boy has a mass of 60 kg. The distance between them is 2.00 m.
Substituting the values into the formula:
F = (6.674 × 10^-11 N(m/kg)^2 * 50 kg * 60 kg) / (2.00 m)^2
Calculating the result:
F = (6.674 × 10^-11 N(m/kg)^2 * 3000 kg^2) / 4.00 m^2
F = (2.0022 × 10^-7 N * kg * m^2) / 4.00 m^2
F = 5.0055 × 10^-8 N
Therefore, the attractive force between the girl and the boy is approximately 5.0055 × 10^-8 N.