The perimeter of a rectangle is 62 inches. If the length of rectangle is four inches less than four times the width find the dimensions.

width --- x

length --- 4x - 4

2x + 2(4x-4) = 62

solve for x

To find the dimensions of the rectangle, we need to set up equations based on the information given.

Let's assume that the width of the rectangle is represented by the variable 'w' (in inches). Therefore, the length of the rectangle would be represented by '4w - 4' (in inches).

The perimeter of a rectangle can be calculated using the formula: P = 2(length + width).

Given that the perimeter is 62 inches, we can set up the equation:

62 = 2((4w - 4) + w)

Simplifying the equation:
62 = 2(5w - 4)

Distributing the 2:
62 = 10w - 8

Adding 8 to both sides:
70 = 10w

Dividing both sides by 10:
w = 7

Now that we have the value of 'w,' we can substitute it back into the expression for the length of the rectangle:

length = 4w - 4
length = 4(7) - 4
length = 28 - 4
length = 24

Therefore, the dimensions of the rectangle are width = 7 inches and length = 24 inches.