AP Physics C
posted by Melly
as she pick up her riders a bus driver traverses four successive displacements represented by the expression (6.30 b)i(4.00 b cos 40)i(4.00 sin 40)j+(3.00 b cos 50)i(3.00 b sin 50)j(5.00 b)j here b represents one city block,a convenient unit of distance of uniform size; i is east; and j is north. the displacements at 40 degree and 50 degree represent travel on roadways in the city that are at these angles to the main eastwest and northsouth streets.(a)draw a map of the successive displacements(b)what total distance did she travel? (c)compute the magnitude and direction of her total displacements.
*Please explain how you got to your answers/ how you found what to add together, etc*

Damon
Well, you will have to draw the map
for displacements add x components and y components separately and for distances:
find each and add
move 1
distance = 6.3
displacement east = 6.3 i
displacement north = 0 j
move 2
distance = 4
displacement east = 4 cos 40 = 3.06 i
displacement north= 4 sin 40 = 2.57 j
move 3
distance = 3
displacement east = 3 cos 50 = 1.93 i
displacement north=3 sin 50 =2.30 j
move 4
distance = 5
displacement east = 0 i
displacement north=5 j
then total distance = 6.3+4+3+5
disp east = 6.33.06+1.93+0 =
disp North = 0 2.57 2.30 5
tan angle = disp east/disp north
it will be in quadrant 3 (south west) here so that angle is south of west 
Damon
oh, put all those in units of b, city blocks :)
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as she pick up her riders a bus driver traverses four successive displacements represented by the expression (6.30 b)i(4.00 b cos 40)i(4.00 sin 40)j+(3.00 b cos 50)i(3.00 b sin 50)j(5.00 b)j here b represents one city block,a … 
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as she pick up her riders a bus driver traverses four successive displacements represented by the expression (6.30 b)i(4.00 b cos 40)i(4.00 sin 40)j+(3.00 b cos 50)i(3.00 b sin 50)j(5.00 b)j here b represents one city block,a …