NaHCO3 + HCl = NaCl + H2O + CO2
The there are .0489 moles of CO2, and HCL is 6M.
find the amount of HCL in mL and the grams of NaHCO3
mols CO2 = 0.0489.
Using the coefficients in the balanced equation, convert mols CO2 to mols NaHCO3.
Then convert g NaHCO3 to mols; as g = mols x molar mass
To find the amount of HCl in milliliters (mL):
Step 1: Calculate the number of moles of CO2 using the given information.
Number of moles = 0.0489 moles
Step 2: Since the CO2 is produced in a 1:1 ratio with HCl, the number of moles of HCl will also be 0.0489 moles.
Step 3: Calculate the volume of HCl using its molarity (6M) and the number of moles.
Volume (in liters) = Number of moles / Molarity
= 0.0489 moles / 6 M
≈ 0.00815 L
Step 4: Convert the volume from liters to milliliters.
1 L = 1000 mL
Therefore, 0.00815 L ≈ 8.15 mL
So, the amount of HCl is approximately 8.15 mL.
To find the grams of NaHCO3:
Step 1: Take the balanced equation:
NaHCO3 + HCl = NaCl + H2O + CO2
Step 2: From the equation, we can see that the ratio of NaHCO3 to CO2 is 1:1. Therefore, the number of moles of NaHCO3 will be equal to the number of moles of CO2.
Step 3: The number of moles of CO2 is given as 0.0489 moles.
Step 4: The molar mass of NaHCO3 is:
Na: 22.99 g/mol
H: 1.01 g/mol
C: 12.01 g/mol
O: 16.00 g/mol
Adding all the atomic weights together:
22.99 + 1.01 + 12.01 + (3 * 16.00) = 84.01 g/mol
Step 5: Calculate the grams of NaHCO3 using its molar mass and the number of moles.
Mass = Number of moles * Molar mass
= 0.0489 moles * 84.01 g/mol
≈ 4.119 g
So, the grams of NaHCO3 is approximately 4.119 g.
To find the amount of HCl in mL, we can use the formula:
moles = Molarity x Volume
Given that the moles of CO2 is 0.0489 and the Molarity of HCl is 6M, we can calculate the volume of HCl in mL.
moles HCl = moles CO2
Volume HCl (in L) = moles HCl / Molarity HCl
Volume HCl (in mL) = Volume HCl (in L) * 1000
moles HCl = 0.0489
Molarity HCl = 6M
Volume HCl (in L) = 0.0489 moles / 6M = 0.00815 L
Volume HCl (in mL) = 0.00815 L * 1000 = 8.15 mL
Therefore, the amount of HCl is 8.15 mL.
Next, to find the grams of NaHCO3, we need to use the formula:
moles = mass / molar mass
Rearranging the formula, we get:
mass = moles x molar mass
Given that the moles of CO2 is 0.0489 and the molar mass of NaHCO3 is:
Na = 22.99 g/mol
H = 1.01 g/mol
C = 12.01 g/mol
O = 16.00 g/mol
Molar mass NaHCO3 = (22.99 g/mol) + (1.01 g/mol) + (12.01 g/mol) + (3 * 16.00 g/mol) = 84.01 g/mol
mass NaHCO3 = 0.0489 moles x 84.01 g/mol = 4.11 g
Therefore, the mass of NaHCO3 is 4.11 grams.