Ty uses the function g(x)=0.5+0.2(x-1) to calculate the cost in dollars of using a calling card to make a long distance call lasting x minutes.The variable x must be a hole number.graph the function then determine the cost of a 10-minute call
Why did the function go to the circus? Because it wanted to call a "long distance" ringmaster! 🎪
To graph the function, we can plot a few points and connect them with a line. Let's choose x-values of 0, 5, 10, 15, and 20 minutes and find the corresponding y-values:
g(0) = 0.5 + 0.2(0 - 1) = 0.5 - 0.2 = 0.3
g(5) = 0.5 + 0.2(5 - 1) = 0.5 + 0.2(4) = 0.5 + 0.8 = 1.3
g(10) = 0.5 + 0.2(10 - 1) = 0.5 + 0.2(9) = 0.5 + 1.8 = 2.3
g(15) = 0.5 + 0.2(15 - 1) = 0.5 + 0.2(14) = 0.5 + 2.8 = 3.3
g(20) = 0.5 + 0.2(20 - 1) = 0.5 + 0.2(19) = 0.5 + 3.8 = 4.3
Now we can plot these points: (0, 0.3), (5, 1.3), (10, 2.3), (15, 3.3), (20, 4.3).
According to our graph, the cost of a 10-minute call would be $2.3. Just remember, don't clown around too much or your long-distance bill might make you shed a tear! 🤡💰
To graph the function g(x) = 0.5 + 0.2(x-1), you can follow these steps:
1. Determine the range of values for x. Since it specifies that x must be a whole number, choose a range of values that includes whole numbers.
2. Plug in the chosen values of x into the function to find the corresponding y-values (cost in dollars).
3. Create a coordinate plane (graph) with the x-axis representing the minutes spent on a long distance call and the y-axis representing the cost in dollars.
4. Plot the points (x, y) on the graph. Connect the points with a smooth line, representing the function g(x).
Now, let's find the cost of a 10-minute call using the function g(x) = 0.5 + 0.2(x-1):
Plug in x = 10 into the function:
g(10) = 0.5 + 0.2(10-1)
= 0.5 + 0.2(9)
= 0.5 + 0.2(9)
= 0.5 + 0.2(9)
= 0.5 + 1.8
= 2.3
Therefore, the cost of a 10-minute call using the function g(x) is $2.30.
Please note that the graph should be plotted with a whole number range for x, even though the cost may have fractional values.