While in Europe, if you drive 125km per day, how much money would you spend on gas in one week if gas costs 1.10 euros per liter and your car's gas mileage is 22.0mi/gal ? Assume that 1euro=1.26dollars.
Convert 125 km to miles. I get about 77.7 miles but you should confirm that.
77.7 mi/day x 7 days/week = about 544 miles but that's approx. You should redo all of the math before and after this sentence.
544 miles x (1 gal/22.0mi) approx 24.7 gallons.
24.7 gallons x (1 L/0.264 gal) = approx 94 L.
94 L x 1.10 er/L = about 103 euros.
Then convert euros to dollars.
To calculate how much money you would spend on gas in one week while driving 125km per day in Europe, you need to follow these steps:
1. Convert kilometers to miles: Since gas mileage is given in miles per gallon, it's better to have the distance in miles. So, convert 125km to miles by multiplying it with the conversion factor: 1 kilometer is approximately equal to 0.621371 miles. Therefore, 125km would be 77.67 miles (rounded to two decimal places).
2. Calculate the total distance driven in a week: To find the total distance driven in a week, multiply the distance per day (77.67 miles) by 7 (number of days in a week). This equals 543.69 miles (rounded to two decimal places).
3. Calculate the number of gallons used in one week: Divide the total distance driven in miles (543.69 miles) by the car's gas mileage (22.0 miles/gallon). This equals 24.71 gallons (rounded to two decimal places).
4. Convert euros to dollars: Since gas costs are given in euros, convert the price per liter to dollars using the given exchange rate. Multiply 1.10 euros with the conversion factor 1.26 dollars/euro. This equals 1.386 dollars (rounded to two decimal places).
5. Calculate the total cost of gas for one week: Multiply the number of gallons used in one week (24.71 gallons) by the cost per gallon (1.386 dollars). This equals 34.28 dollars (rounded to two decimal places).
Therefore, you would spend approximately 34.28 dollars on gas in one week while driving 125km per day in Europe.