algebra

posted by .

The velocity of an object fired directly upward is given by the equation V=40-18t, where t is in seconds. when will the velocity be between 22 and 31 feet per second? write and solve a compound inequality and graph the solution on a number line.

  • algebra -

    22<40-18t<31
    subtract 40 from all sides and then divide by -18. Flip the signs afterwards.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Algebra

    THe function h(t)=-16t^2+v0t+h0 describes the height in feet above the ground h(t) of an object thrown vertically from a height of h0 feet, with an initial velocity of v0 feet per second, if there is no air friction and t is the time …
  2. Math

    If an object is propelled upward from ground level with initial velocity of 55 feet per second, it's height h in feet t seconds later is given by the equation H=-16t^2+55t. after how many seconds does the object hit ground?
  3. math

    Could someone please show me how to do these problems?
  4. math

    Could someone please show me how to do these problems?
  5. Physics

    I don't understand this at all! use the position equation s=-16t^2 +v0t+s0 to write a function that represents the situation. Find the average rate of change from t1 to t2. a) An object is thrown upward from a height of 6 feet at a …
  6. Sam E

    Let v(t)=t^2−3t be the velocity, in feet per second, of an object at time t , in seconds. (c) What is the meaning of the quantity v(4)?
  7. Math Help

    Let v(t)=t^2−3t be the velocity, in feet per second, of an object at time t , in seconds. (c) What is the meaning of the quantity v(4)?
  8. Math

    In physics, one learns that the height of an object thrown upward from an initial height of h0 feet with an initial velocity of v0 (in feet per second) is given by the formula h(t)=−16t^2+v0t+h0 feet where t is the amount of …
  9. Maths

    object thrown upward from an initial height of h0 feet with an initial velocity of v0 (in feet per second) is given by the formula h(t)=−16t^2+v0t+h0 feet where t is the amount of time in seconds after the ball was thrown. Also, …
  10. College Algebra

    If an object is propelled upward from a height of s feet at an initial velocity of v feet per​ second, then its height h after t seconds is given by the equation hequals minus16t squaredplusvtplus​s, where h is in feet. If the …

More Similar Questions