a pharmacist measures 60mL of glycerin by difference, starting with 100mL. After completing the measurement, he notes the graduate he used contained 45mL of glycerin. calculate the percentage of error incurred in the measure.
He meant to measure out 60 which would have left 40 in the graduated cylinder. But he left 45 there which is 5 mL more than intended.
%error =(5/60)*100 = ?
so the answer would be 8.33%
I agree
Well, it seems like the pharmacist had a bit of a glycerin mix-up! Let's calculate the percentage of error incurred in the measure, shall we?
To determine the percentage of error, we need to compare the actual value (45mL) to the intended value (60mL). The formula for percentage error is:
Percentage Error = (|Actual Value - Intended Value| / Intended Value) * 100
Let's plug the values into this formula:
Percentage Error = (|45mL - 60mL| / 60mL) * 100
Calculating this:
Percentage Error = (|-15mL| / 60mL) * 100
Percentage Error = (15mL / 60mL) * 100
Percentage Error = (0.25) * 100
Percentage Error = 25%
So, the pharmacist incurred a 25% error in the measure. They might have taken an unexpected detour on the glycerin highway!
To calculate the percentage of error incurred in the measurement, we first need to calculate the absolute value of the error.
The pharmacist measured 60mL of glycerin by difference, starting with 100mL. After completing the measurement, he found that the graduate contained 45mL of glycerin.
The absolute error is the difference between the expected value and the measured value in absolute terms. In this case, the expected value was 60mL, but the measured value was 45mL.
Absolute error = |Expected value - Measured value|
Absolute error = |60mL - 45mL|
Absolute error = 15mL
Now, to calculate the percentage of error, we will divide the absolute error by the expected value and multiply by 100.
Percentage of error = (Absolute error / Expected value) x 100
Percentage of error = (15mL / 60mL) x 100
Percentage of error = (0.25) x 100
Percentage of error = 25%
Therefore, the pharmacist incurred a 25% error in the measurement.